(g-4)(g+4)=g^2-16

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Solution for (g-4)(g+4)=g^2-16 equation: 



(g-4)(g+4)=g^2-16

We move all terms to the left:

(g-4)(g+4)-(g^2-16)=0

We use the square of the difference formula

g^2-(g^2-16)-16=0

We get rid of parentheses

g^2-g^2+16-16=0

We add all the numbers together, and all the variables

=0

g=0/1

g=0

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